Matemática básica
Como faço???
[tex] \sqrt{4 + 2 \sqrt{3} } = 1 + \sqrt{3} \\ \sqrt{1 + 3 + 2 \sqrt{3} } = 1 + \sqrt{3} \\ \sqrt{1 + 2 \sqrt{3} + 3 }= 1 + \sqrt{3} \\ {a}^{2} + 2ab + {b}^{2} = (a + b) {}^{2} \\ \sqrt[ \cancel2] { {\left(1 + \sqrt{3} \right)}^{ \cancel2} } = 1 + \sqrt{3} \\ \color{green}1 + \sqrt{3} = 1 + \sqrt{3} [/tex]
[tex]{\huge\boxed { {\bf{E}}}\boxed { \red {\bf{a}}} \boxed { \blue {\bf{s}}} \boxed { \gray{\bf{y}}} \boxed { \red {\bf{}}} \boxed { \orange {\bf{M}}} \boxed {\bf{a}}}{\huge\boxed { {\bf{t}}}\boxed { \red {\bf{h}}}} \\ \boxed{ \displaystyle\int_ \empty ^ \mathbb{C} \frac{ - b \: ± \: \sqrt{ {b}^{2} - 4 \times a \times c } }{2 \times a} d{ t } \boxed{ \boxed{ \mathbb{\displaystyle\Re}\sf{ \gamma \alpha }\tt{ \pi}\bf{ \nabla}}}} \\ {\boxed{ \color{blue} \boxed{ 06 |01|23 }}}{\boxed{ \color{blue} \boxed{Espero \: ter \: ajudado \: ☆}}}[/tex]
